## The dog and the hare

There is an inverse relationship between the dog's leaps and the hare's leaps, meaning a hare's leap is worth 2/5 dog's leaps. We can then write:

number of hops | hop value | |

dog jumps | 5 | 2 |

hare leaps | 8 | 5 |

Since the relationship between the hops is inverse, we will perform an inverted multiplication, that is, we will multiply the dog's 5 hops by the value of the hare's jump (5) and multiply the 8 hare's hops by the value of the dog's hopping (2). Thus we will have: 5 x 5 = 25 (for the dog) and 8 x 2 = 16 (for the hare).

At any moment, the dog will be taking a difference of 25 - 16 = 9 jumps. Since the distance between them is 36 dog jumps, it follows that the dog will have to travel this distance 36/9 = 4 times to reach the hare. Now, by multiplying the dog factor (25) by 4, we get: 25 x 4 = ** 100 dog jumps**.

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